32x^2+12x=27

Solution for 32x^2+12x=27 equation:

32x^2+12x=27

We move all terms to the left:

32x^2+12x-(27)=0

a = 32; b = 12; c = -27;
Δ = b2-4ac
Δ = 122-4·32·(-27)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-60}{2*32}=\frac{-72}{64}
=-1+1/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+60}{2*32}=\frac{48}{64}
=3/4
$